5 Variable K Map
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5 Variable K Map. By minimization we imply a function with minimum number of terms and each term with lowest. So, for a boolean function consisting of two variables, we draw a 2 x 2 k map.
Determine the type of given boolean expression. It might be in the form of sop (minterms) or pos (max terms). Groups must contain only 1 (and x if don't care is allowed).
The 3 variable kmap has 8 cells because as stated above it has 3 variables so the possible inputs would be 2³=8.
It is a way of minimizing the boolean functions using diagrams which are made up of squares. • there are two possibilities of grouping 16 adjacent min terms. Groups must contain 1, 2, 4, 8, 16 (2 n) cells. A b c d e 0 1 x:
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